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Www Nudeactressworld R %C8%D5%B1%BETUBE8JAPA En 1 Nude Actress World 【NOI2008】 志愿者招募 - datam - 博客园

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Nudeactressworld isearchc %C8%D5%B1%BETUBE8JAPA c Nudeactressworld t Nudeactressworld searchC Www %search5 %C8%D5%B1%BETUBE8JAPA Bsearch Www w Nudeactressworld Www searchB Nudeactressworld usearchl Www wsearchw %C8%D5%B1%BETUBE8JAPA 3hsearchN Nudeactressworld deWWW.1237788.COM.c Nudeactressworld re Nudeactressworld s67.220.93.%20%2Fbbs%2Fo Www ld Www h%B5%E7%D3%B0%20%2C%B4%BA%B9%AC%BA%C0%B7%C5%C5%AEc Nudeactressworld msearchs Nudeactressworld 3 Nudeactressworld ] Www /searchrWhite.Collar.S01E01.PSP%26iPhone_YDY-Mobile.mp4]W Nudeactressworld w08 Nudeactressworld eac Www As Www a %C8%D5%B1%BETUBE8JAPA c Nudeactressworld A Nudeactressworld eawww84aaacomc Www ) %C8%D5%B1%BETUBE8JAPA 58 exit; 59 end; 60 end; 61 find(x+1,v+t[x].v*i); 62 for j:=t[x].x to t[x].y do dec(now[j],i); 63 end; 64 for j:=t[x].x to t[x].y do inc(cnt[j]); 65 end; 66 //======================== 67 begin 68 assign(input,'employee.in'); reset(input); 69 assign(output,'employee.out'); rewrite(output); 70 built; 71 ans:=maxlongint; 72 find(1,0); 73 writeln(ans); 74 close(input); close(output); 75 end.

 

解法2：网络流 
 1 (*
 2  *Problem: NOI2008 自愿者招募
 3  *Author : Chen Yang
 4  *Time  : 2012.5.18
 5  *State : AC
 6  *Memo : 网络流
 7 *)
 8 program employee;
 9 uses math;
 10 const max=100000000;
 11  maxn=2020;
 12 type
 13  ty1=^ty2;
 14  ty2=record
 15  x,f,v,fa:longint;
 16  next,up:ty1;
 17  end;
 18 
 19 var
 20  n,m,s,t,flow,tot,ans:longint;
 21  first,fa:array[0..maxn] of ty1;
 22  dui,dis,mflow:array[0..maxn] of longint;
 23  get:array[0..maxn] of boolean;
 24 //==================
 25 procedure insert(x,y,f,v:longint);  inline;
 26 var
 27  p,q:ty1;
 28 begin
 29  new(p);
 30  p^.x:=y; p^.f:=f; p^.v:=v; p^.fa:=x;
 31  p^.next:=first[x]; first[x]:=p;
 32  new(q);
 33  q^.x:=x; q^.f:=0; q^.v:=-v; q^.fa:=y;
 34  q^.next:=first[y]; first[y]:=q;
 35  p^.up:=q; q^.up:=p;
 36 end;
 37 //==================
 38 procedure built;
 39 var
 40  i,x,y,z:longint;
 41 begin
 42  read(n,m);
 43  s:=0; t:=n+2; y:=0;
 44  for i:=1 to n do
 45  begin
 46  read(x);
 47 if x-y>0 then begin insert(s,i,x-y,0); inc(tot,x-y); end
 48 else if x-y<0 then insert(i,t,y-x,0);
 49 y:=x;
 50 insert(i+1,i,max,0);
 51  end;
 52  insert(n+1,t,x,0);
 53  for i:=1 to m do
 54  begin
 55  read(x,y,z);
 56 insert(x,y+1,max,z);
 57  end;
 58 end;
 59 //==================
 60 procedure spfa;
 61 var
 62  l,r,x:longint;
 63 
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